High School

We appreciate your visit to Upon the combustion of 24 g of CH₄ Molar mass 16 g mol with an excess of oxygen according to the given reaction text CH. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Upon the combustion of 24 g of CH₄ (Molar mass = 16 g/mol) with an excess of oxygen according to the given reaction:

\[ \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \]

What is the mass of CO₂ (Molar mass = 44 g/mol) obtained?

A. 24 g

B. 33.9 g

C. 66.9 g

D. 29.39 g

Answer :

Final answer:

The mass of CO2 obtained is 66 g.

Explanation:

To find the mass of CO2 obtained, we need to calculate the number of moles of CH4 and then use the stoichiometry of the balanced equation to find the number of moles of CO2. Given that the molar mass of CH4 is 16 g/mol, we can convert the mass of CH4 to moles by dividing it by the molar mass. 24 g of CH4 is equal to 24/16 = 1.5 moles of CH4. According to the balanced equation, 1 mole of CH4 reacts to produce 1 mole of CO2. Therefore, the number of moles of CO2 obtained is also 1.5 moles. Finally, we can convert the moles of CO2 to mass by multiplying it by the molar mass of CO2 which is 44 g/mol. So, the mass of CO2 obtained is 1.5 * 44 = 66 g.

Learn more about Combustion of CH4 here:

https://brainly.com/question/32115164

#SPJ11

Thanks for taking the time to read Upon the combustion of 24 g of CH₄ Molar mass 16 g mol with an excess of oxygen according to the given reaction text CH. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada