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The combined SAT scores for the students at a local high school are normally distributed with a mean of 1489 and a standard deviation of 295. The local college includes a minimum score of 1017 in its admission requirements. What percentage of students from this school earn scores that fail to satisfy the admission requirement?

Answer :

Final answer:

To calculate the percentage of students from this school that fail to satisfy the admission requirement you can use the Z-score. This is done by subtracting the mean from the specific score, divided by the standard deviation. The resulting Z-score of -1.6, which can be looked up in the standard normal distribution table, correlates to about 5.48% of students

Explanation:

To solve this problem, we can use the concept of Z-score in statistics. The Z-score is a measure of how many standard deviations an element is from the mean. In your case the admissions score of 1017 is below the mean SAT score of 1489 for the students at the local school.

Firstly, we calculate the Z-score using the formula Z = (X - μ) / σ. In this case, μ (the mean) is 1489, σ (the standard deviation) is 295, and X (the specific score in question) is 1017.

Therefore, Z = (1017 - 1489) / 295 = -1.6 approximately.

After calculating the Z-score, you need to look up this Z-score in a standard normal distribution table or use a calculator with such functionality. This Z-score of -1.6 correlates to approximately 0.0548 (or about 5.48%) in the standard normal distribution table.

This suggests that approximately 5.48% of students from this school earn scores that fail to satisfy the admission requirement of the local college.

Learn more about Z-Score Calculation here:

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