1. The introduction to this experiment draws a parallel between the formation of a Grignard reagent and the oxidative addition step in the Suzuki reaction.

b. Why is the Grignard reagent you drew above more water-reactive than the organopalladium intermediate you drew above? (Note: Grignard reagents are destroyed by water, but you will be using water as a solvent in the Suzuki reaction.)

Question

25-12-2023
Chemistry

High School

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1. The introduction to this experiment draws a parallel between the formation of a Grignard reagent and the oxidative addition step in the Suzuki reaction.

b. Why is the Grignard reagent you drew above more water-reactive than the organopalladium intermediate you drew above? (Note: Grignard reagents are destroyed by water, but you will be using water as a solvent in the Suzuki reaction.)

Answer :

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chintugraveiens96 chintugraveiens96 · Answer 1 · 2025-02-23T05:08:45-05:00

The Grignard reagent is more water-reactive than the organopalladium intermediate because the Grignard reagent is a strong base and a strong nucleophile. The organopalladium intermediate is less reactive because it is stabilized by the palladium atom.

When water reacts with a Grignard reagent, it can produce an alcohol and hydrogen gas. This reaction occurs because the Grignard reagent is a strong base and a strong nucleophile, and it can attack the water molecule to form an alcohol.

In addition, the hydrogen gas is produced because the Grignard reagent can also react with water to produce hydrogen gas.

On the other hand, the organopalladium intermediate is less reactive because it is stabilized by the palladium atom. This stabilization occurs because the palladium atom has a partially filled d-orbital, which can accept electrons from the organic group.

As a result, the organopalladium intermediate is less likely to react with water, and it is not destroyed by water like the Grignard reagent.

To know more about the Grignard reagent https://brainly.com/question/12961083

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