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Answer :
Final answer:
The correct justification for Statement 4 (∠3 ≅ ∠6) is the transitive property of equality, following from the earlier proven statements that ∠7 ≅ ∠6 and ∠3 ≅ ∠7.
Explanation:
The correct justification for statement 4 (∠3 ≅ ∠6) in the two-column proof provided in the question is the transitive property of equality. This property states that if a = b and b = c, then a = c. In the context of this proof:
- Statement 2 declared angles 7 and 6 to be congruent (∠7 ≅ ∠6)
- Statement 3 declared angles 3 and 7 to be congruent (∠3 ≅ ∠7)
Following the transitive property, if ∠7 ≅ ∠6 and ∠3 ≅ ∠7, then it logically follows that ∠3 is congruent to ∠6, hence ∠3 ≅ ∠6 (Statement 4)
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Final answer:
The justification for statement 4 in the proof, claiming that ∠3 and ∠6 are congruent, is the Transitive property of equality. This is because it follows the premises that ∠7 is congruent to ∠6 and ∠3 is congruent to ∠7.
Explanation:
The justification for statement 4, ∠3 ≅ ∠6, of the two-column proof would be (d) the Transitive property of equality. Let's understand why. Initially, we have the Given that line jk is parallel to line lm. The second step establishes that ∠7 ≅ ∠6, usually through the Corresponding Angles Postulate (or Theorem), which states that when a transversal intersects parallel lines, corresponding angles are congruent. The third step establishes ∠3 ≅ ∠7, and hence by the transitive property of equality, which holds that if ∠7 ≅ ∠6 (from statement 2) and ∠3 ≅ ∠7 (from statement 3), we can deduce that ∠3 ≅ ∠6. Hence, this proof is validated.
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