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Answer :
The magnitude of the average EMF is E = 63.7 mV
Given is that there are 119 turns,
hence N= 119 .
The coil's radius is 2.51 cm
which is equal to r = 0.0251 m.
Time interval given is t=0.169 s
a rise in the magnetic field from 51.5 mT to 97.3 mT
Using the Faraday law of induction, the EMF of a magnetic field is calculated.
EMF = -NA∆B/∆t
The area of the coil circle is given by
Area = πr²
area = 3.14 × 0.0251 × 0.0251
area = 0.00197823 m²
area = 1.97823 × [tex]10^-^3[/tex] m²
Thus E = - 119 × 1.97823 × [tex]10^-^3[/tex] × ( 97.3 × [tex]10^-^3[/tex] - 51.5 × [tex]10^-^3[/tex]) / 0.169
E = 235.4 × [tex]10^-^3[/tex] ( 45.8 × [tex]10^-^3[/tex] ) / 0.169
E = 10781.32 × [tex]10^-^6[/tex] / 0.169
E = 63794.79 × [tex]10^-^6[/tex] V
E = 6.379479 × [tex]10^4[/tex] × [tex]10^-^6[/tex] × [tex]10^3[/tex]
E = 6.37 × 10
E = 63.7 mV
The magnitude is then equal to 63.7 millivolts (EMF).
To know more about EMF you may visit the link
https://brainly.com/question/15121836
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