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A 93 kg football player is hit by a tackler who drives him to the right with a force of 1175 N. If the feet of the player who was hit are off the ground so we can neglect ground reaction force, what is the acceleration of the football player?

Answer :

The acceleration of the 93 kg football player after being hit with a force of 1175 N is 12.63 m/s^2, as calculated using Newton's second law of motion.

The question asks about the acceleration of a 93 kg football player after being hit with a force of 1175 N. According to Newton's second law of motion, acceleration ( extit{a}) can be calculated by dividing the Net Force (extit{F}) by the mass ( extit{m}) of the object, as expressed in the formula extit{a} = extit{F}/ extit{m}. In this case, the Net Force is simply the force of the tackler, since other forces are negligible.

To find the acceleration, we divide 1175 N by 93 kg, which yields:

Acceleration = 1175 N / 93 kg = 12.63 m/s2

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