High School

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The length of a standard jewel case is 5 cm more than its width. The area of the rectangular top of the case is 176 cm².

Answer :

Final answer:

The problem is about using algebraic relationships to solve a geometry problem involving the length and width of a rectangular jewel case. The student would use an algebraic equation to solve for unknown dimensions, given the area of the rectangle.

Explanation:

The topic in question here is in the field of Mathematics, specifically Algebra and Geometry. Given that the length of the jewel case is 5 cm more than its width, and the area of the rectangular top of the case is 176 cm², we can establish the following:

Let's denote the width of the case to be 'x' cm. Then the length of the jewel case will be 'x + 5' cm. The area of a rectangle is calculated by width * length, which in this case equals to x * (x + 5). As it's given the area is 176 cm², we get the equation x * (x + 5) = 176.

By solving this equation, the student should be able to determine the width and length of the jewel case. This is a typical problem involving the application of algebraic equations in geometry.

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