We appreciate your visit to A sealed plastic syringe has a pressure of 97 8 kPa at a temperature of 402 K If the syringe s temperature changes to 251. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
To find the new pressure when the temperature is changed from 402 K to 251 K, we can use Gay-Lussac's Law. The new pressure will be approximately 61.3 kPa.
Explanation:
When a sealed plastic syringe undergoes a change in temperature, its pressure also changes. In this case, the original pressure is 97.8 kPa at a temperature of 402 K.
To find the new pressure when the temperature is 251 K, we can use Gay-Lussac's Law.
Gay-Lussac's Law states that the pressure of a gas is directly proportional to its temperature, as long as the volume and amount of gas are constant.
We can use the formula P₁/T₁ = P₂/T₂, where P₁ and T₁ are the initial pressure and temperature, and P₂ and T₂ are the final pressure and temperature.
Plugging in the given values, we have 97.8 kPa / 402 K = P₂ / 251 K.
Solving for P₂, we get P₂ = (251 K * 97.8 kPa) / 402 K ≈ 61.3 kPa.
Learn more about pressure here:
https://brainly.com/question/31367519
#SPJ11
Thanks for taking the time to read A sealed plastic syringe has a pressure of 97 8 kPa at a temperature of 402 K If the syringe s temperature changes to 251. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
