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**Question 1:** Find the first six terms of the sequence given by \( a_1 = -4 \) and \( a_n = a_{n-1} + 8 \).

A. 0, 8, 16, 24, 32, 40
B. 12, 20, 28, 36, 44, 52
C. 4, 12, 20, 28, 36, 44
D. 4, 8, 16, 24, 32, 40

**Question 2:** Find the first six terms of the sequence given by \( a_1 = -8 \) and \( a_n = 5a_{n-1} \).

A. -8, -40, -200, -1000, -5000, -25,000
B. 8, -40, -35, -30, -25, -20
C. 0, 5, -40, -35, -30, -25
D. 40, -200, -1000, -5000, -25,000, -125,000

Answer :

The correct answer is option is 3) 4, 12, 20, 28, 36, 44 and option is 1) -8,-40, -200,-1000,-5000, -25,000.

Question 1= The given sequence is a1 = -4 and an = an-1 + 8.

Here, to find the first six terms of the given sequence, we need to substitute the values of n from 1 to 6.

So, the first six terms of the given sequence are as follows:

The first term, a1 = -4.

Second term, a2 = a1 + 8 = -4 + 8 = 4.

Third term, a3 = a2 + 8 = 4 + 8 = 12.

Fourth term, a4 = a3 + 8 = 12 + 8 = 20.

Fifth term, a5 = a4 + 8 = 20 + 8 = 28.

Sixth term, a6 = a5 + 8 = 28 + 8 = 36.

So, the first six terms of the given sequence are -4, 4, 12, 20, 28 and 36.

Hence, the correct option is 3) 4, 12, 20, 28, 36, 44.

Question 2= The given sequence is a1 = -8 and an = 5an-1.

Here, to find the first six terms of the given sequence, we need to substitute the values of n from 1 to 6.

So, the first six terms of the given sequence are as follows:

First term, a1 = -8.

Second term, a2 = 5a1 = 5(-8) = -40.

Third term, a3 = 5a2 = 5(-40) = -200.

Fourth term, a4 = 5a3 = 5(-200) = -1000.

Fifth term, a5 = 5a4 = 5(-1000) = -5000.

Sixth term, a6 = 5a5 = 5(-5000) = -25,000.

So, the first six terms of the given sequence are -8, -40, -200, -1000, -5000 and -25,000.

Hence, the correct option is 1) -8,-40, -200,-1000,-5000, -25,000.

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