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An automobile engine slows down from 3700 rpm to 1500 rpm in 2.00 s.

1. Calculate its angular acceleration, assuming it is constant.
2. Calculate the total number of revolutions the engine makes in this time.

Answer :

Final answer:

The angular deceleration of the automobile engine is -115.3 rad/s². To calculate the total number of revolutions, the formula for displacement in uniformly accelerated linear motion is used, the result of which is converted to revolutions.

Explanation:

To calculate the angular acceleration, you first need to convert the given speeds from revolutions per minute (rpm) to radians per second (rad/s). The conversion factor is (2π rad)/(1 rev). This gives you 3700 rpm = 3700 * (2π rad) / (60 s) = 387.6 rad/s and 1500 rpm = 1500 * (2π rad) / (60 s) = 157.1 rad/s.

Next, you use the formula for angular acceleration, which is α = Δω / Δt, where Δω is the change in angular velocity and Δt is the elapsed time. So, Δω = ω_final - ω_initial = 157.1 rad/s - 387.6 rad/s = -230.5 rad/s. Thus, the angular acceleration is α = Δω / Δt = -230.5 rad/s / 2.00 s = -115.3 rad/s². The minus sign indicates that it is a deceleration.

To calculate the total number of revolutions, we can make use of the formula for displacement in uniformly accelerated linear motion, Δθ = ω_initial*t + 0.5*α*t², where Δθ is in radians. Converting to revolutions, and substituting the known values, we get the total number of revolutions.

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