High School

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An electron moves to the right in the plane of the page at a velocity of [tex]0.5 \times 10^m/s[/tex]. A magnetic field of [tex]2[/tex] tesla is also in the plane of the page at an angle of [tex]30^\circ[/tex] above the direction of motion.

What are the magnitude and direction of the force on the charge?

A. [tex]8 \times 10^{-°} \, \text{N}[/tex], out of the page
B. [tex]8 \times 10^{-°} \, \text{N}[/tex], into the page
C. [tex]8 \times 10^{-10} \, \text{N}[/tex], along the page
D. [tex]8 \times 10^{-12} \, \text{N}[/tex], into the page
E. [tex]8 \times 10^{-12} \, \text{N}[/tex], out of the page

Answer :

The magnitude and direction of the force on the electron can be determined using the formula for the magnetic force on a moving charged particle.

Given the velocity of the electron, the magnetic field strength, and the angle between the velocity and the magnetic field, we can calculate the force. The correct answer is (d) 8×10-12 N, into the page.

The formula for the magnetic force on a moving charged particle is given by F = q * v * B * sin(θ), where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.

In this case, the electron has a negative charge, and its velocity is 0.5×10 m/s to the right in the plane of the page. The magnetic field has a strength of 2 tesla and is at an angle of 30° above the direction of motion.

Since the electron has a negative charge, the force on it will be in the opposite direction to the velocity. Therefore, the force will be into the page.

Using the formula for the magnetic force, we can calculate the magnitude of the force by substituting the given values: F = (1.6 × 10^-19 C) * (0.5 × 10 m/s) * (2 T) * sin(30°).

Learn more about magnetic force : brainly.com/question/31321824

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