We appreciate your visit to Lin and Gina each walk at a steady rate from school to the library Lin can walk 13 miles in 5 hours and Gina can. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
Lin arrives at the library at 4:15 PM and Gina arrives at 4:18 PM.
Explanation:
Lin walks 13 miles in 5 hours, so his rate is 13 miles / 5 hours = 2.6 miles per hour.
Gina walks 25 miles in 10 hours, so her rate is 25 miles / 10 hours = 2.5 miles per hour.
They each walk 3 1/4 miles to the library, which takes them:
- Lin: 3.25 miles / 2.6 miles per hour = 1.25 hours
- Gina: 3.25 miles / 2.5 miles per hour = 1.3 hours
They both leave school at 3 o'clock, so to find out what time they each arrive at the library, we add their walking times to their departure times:
- Lin: 3 o'clock + 1.25 hours = 4:15 PM
- Gina: 3 o'clock + 1.3 hours = 4:18 PM
Thanks for taking the time to read Lin and Gina each walk at a steady rate from school to the library Lin can walk 13 miles in 5 hours and Gina can. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada