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Answer :
Final answer:
The final velocity of a freight train that accelerates at a rate of 0.0700 m/s² for 8.00 minutes, starting with an initial velocity of 4.00 m/s, is 37.60 m/s.
Explanation:
To determine the final velocity of a freight train that accelerates at a certain rate, we can use the kinematic equation:
v = u + at
where:
- v is the final velocity,
- u is the initial velocity,
- a is the acceleration,
- t is the time.
Given that the initial velocity (u) is 4.00 m/s, the acceleration (a) is 0.0700 m/s², and the time (t) is 8.00 minutes, which we need to convert into seconds:
8.00 minutes = 8.00 × 60 seconds = 480 seconds
Now, we can plug these values into the kinematic equation:
v = 4.00 m/s + (0.0700 m/s² × 480 s)
Calculate the product of acceleration and time, then add the initial velocity:
v = 4.00 m/s + 33.60 m/s
v = 37.60 m/s
Therefore, the final velocity of the freight train after accelerating for 8.00 minutes with an acceleration of 0.0700 m/s² from an initial velocity of 4.00 m/s is 37.60 m/s.
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