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Answer :
A light beam is incident to a medium with index of refraction equal to 1.75. The critical angle is approximately 34.8 degrees.So option d is correct.
To find the critical angle (θc) when a light beam is incident on a medium with an index of refraction of 1.75 and the second medium is air, we can use Snell's law:
n1 × sin(θ1) = n2 × sin(θ2)
Where:
n1 = index of refraction of the first medium (incident medium)
θ1 = angle of incidence
n2 = index of refraction of the second medium (refracted medium)
θ2 = angle of refraction
In this case, the incident medium is the medium with an index of refraction of 1.75, and the refracted medium is air, which has an index of refraction close to 1 (approximately 1).
Since the critical angle occurs when the angle of refraction (θ2) is 90 degrees, we can rewrite Snell's law as:
n1 × sin(θ1) = n2 × sin(90°)
Substituting the values, we have:
1.75 × sin(θ1) = 1 × sin(90°)
sin(θ1) = 1 / 1.75
θ1 ≈ 34.8 degrees
The critical angle is approximately 34.8 degrees.
Therefore option d is correct.
To learn more about Snell's law visit: https://brainly.com/question/31432930
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