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Balance the following chemical reaction equations (with the first reactant always having a stoichiometric coefficient of |1|). Use the tabulated heats of formation and specific heat capacity for the following reactions at the specified conditions. a) nitrogen (N2) and oxygen (O2) producing nitrogen dioxide (NO2) at 25C b) nitrogen (N2) and oxygen (O2) producing nitrogen dioxide (NO2) at 150C c) n-butane(g) and oxygen (O2) producing carbon monoxide and liquid water at 25C d) n-butane(g) and oxygen (O2) producing carbon monoxide and liquid water at 90C e) liquid sodium sulfate and carbon monoxide react to form liquid sodium sulfide and carbon dioxide at 25C

Answer :

Final answer:

The chemical reactions were balanced by ensuring the reactants and products tally on both sides of the equation, for reactions including those between nitrogen, oxygen, butane and sodium sulfate. The temperature does not impact the balance.

Explanation:

This is how we balance the given chemical reaction equations:

a) Nitrogen (N2) and oxygen (O2) producing nitrogen dioxide (NO2) at 25C:
The balanced reaction is N2 + 2O2 —> 2NO2

b) Nitrogen (N2) and oxygen (O2) producing NO2 at 150C: The reaction stays the same regardless of the temperature.

c) n-Butane (C4H10) and oxygen (O2) producing carbon monoxide (CO) and liquid water (H2O) at 25C:
The balanced reaction is C4H10 + 5O2 —> 4CO + 5H2O

d) n-Butane and oxygen producing CO and H2O at 90C: The reaction stays the same regardless of the temperature.

e) Sodium sulfate (Na2SO4) and carbon monoxide (CO) react to form sodium sulfide (Na2S) and carbon dioxide (CO2) at 25C:
The balanced reaction is Na2SO4 + 2CO —> Na2S + 2CO2

Remember, balancing these chemical reaction equations is crucial for understanding stoichiometry and reaction dynamics in chemistry.

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