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Imagine two rigid chambers separated by a rigid membrane that is freely permeable to water but impermeable to glucose. Side 1 contains a 10 percent glucose solution, and side 2 contains pure water. At equilibrium, what will be the situation?

Answer :

Final answer:

In this osmosis scenario, water will move from side 2 (pure water) to side 1 (10% glucose solution) to try to dilute the glucose solution. At equilibrium, both sides will have an equal concentration, but the water level will be higher on the side with the glucose solution.

Explanation:

This scenario represents a common concept in Biology called osmosis. Osmosis is a process that involves the movement of water across a semipermeable membrane from an area of low solute concentration (pure water, in this case) to an area of high solute concentration (the 10% glucose solution, in this case), until equilibrium is reached.

At equilibrium in this setup, the water would have diffused from side 2 (pure water) to side 1 (glucose solution), in an attempt to dilute the glucose solution. As a result, both sides of the system will have an equal concentration and the water level will be higher on the side with the glucose solution.

This is because the membrane is rigid and only lets water through. The glucose molecules remain consistent on side 1 and do not travel to side 2 because the membrane is impermeable to glucose.

Learn more about Osmosis here:

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