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Each month, Barry makes three transactions in his checking account:

- He deposits [tex]$\$700$[/tex] from his paycheck.
- He withdraws [tex]$\$150$[/tex] to buy gas for his car.
- He withdraws [tex]$\$400$[/tex] for other expenses.

If his account balance is [tex]$1,900$[/tex] at the end of the 1st month, which recursive equation models Barry's account balance at the end of month [tex]$n$[/tex]?

A. [tex]f(1) = 1,900[/tex]
[tex]f(n) = f(n-1) + 700, \text{ for } n \geq 2[/tex]

B. [tex]f(1) = 1,900[/tex]
[tex]f(n) = f(n-1) - 150, \text{ for } n \geq 2[/tex]

C. [tex]f(1) = 1,900[/tex]
[tex]f(n) = f(n-1) + 150, \text{ for } n \geq 2[/tex]

D. [tex]f(1) = 1,900[/tex]
[tex]f(n) = 150 \cdot f(n-1), \text{ for } n \geq 2[/tex]

Answer :

To solve this problem and find the correct recursive equation for Barry's account balance, let's carefully look at his transaction pattern each month.

1. Understand the initial account balance:
- Barry starts with an account balance of \[tex]$1,900 at the end of the 1st month. This is defined as \( f(1) = 1,900 \).

2. Calculate the net change in his account per month:
- He deposits \$[/tex]700 from his paycheck.
- He withdraws \[tex]$150 for gas.
- He withdraws \$[/tex]400 for other expenses.

3. Determine the total monthly change:
- Total monthly change = Deposit from paycheck - Withdraw for gas - Withdraw for expenses
- Total monthly change = \[tex]$700 - \$[/tex]150 - \[tex]$400 = \$[/tex]150

4. Formulate the recursive equation:
- The balance at the end of each month depends on the balance at the end of the previous month, plus the monthly net change.
- Therefore, the recursive equation for Barry's account balance at the end of month [tex]\( n \)[/tex] is:
[tex]\[
f(n) = f(n-1) + 150, \text{ for } n \geq 2
\][/tex]

Given the above steps, the correct option is:
C.
[tex]\( f(1) = 1,900 \)[/tex]
[tex]\( f(n) = f(n-1) + 150, \text{ for } n \geq 2 \)[/tex]

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