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Wolves are sometimes observed to have black coats and blue eyes. Assume that these traits are controlled by single locus genes and are located on different chromosomes. Assume further that normal coat color (N) is dominant to black (n) and brown eyes (B) are dominant to blue (b).

Suppose the alpha male and alpha female of a pack are black with blue eyes (alpha male) and normal colored with brown eyes (alpha female), respectively. The female is heterozygous for both traits and the male is homozygous for both traits.

What would be the genotypic and phenotypic ratio of their offspring? (Show Punnett square.)

Answer :

The answer is
genotypic ratio: 1 : 1 : 1 : 1
phenotypic ratio: 1 : 1 : 1 : 1

Alpha male phenotype: homozygous black fur and homozygous blue eyes
Alpha male genotype: nnbb

Alpha female phenotype: heterozygous normal fur and heterozygous brown eyes
Alpha female genotype: NnBb

According to the Punnet square, their offspring will have the following ratios:
genotypic ratio - 1 : 1 : 1 : 1 (NnBb,


Nnbb




nnBb




nnbb)
phenotypic ratio - 1 : 1 : 1 : 1 (normal fur and brown eyes (NnBb), normal fur and blue eyes (Nnbb), black fur and brown eyes (nnBb), and black fur and blue eyes (nnbb))

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Rewritten by : Barada

Final answer:

The genotypic ratio of the offspring will be 100% Nn for coat color and 100% Bb for eye color, phenotypically they will all have normal coat color and brown eyes. This is because both traits follow the rule of dominance, where one allele (N for coat color, B for eye color) is dominant over the other.

Explanation:

The question is asking about the genotypic and phenotypic ratios of the offspring of two wolves with different traits. The male is black with blue eyes (nnbb), and the female is normal coated with brown eyes (NbBb). It should be noted that the traits are controlled by single locus genes and are located on different chromosomes.

To determine the genotypic and phenotypic ratios, we must use Punnett squares. For coat color, the Punnett square will be set up as follows:

n n
N Nn Nn
b Bb Bb
The genotypic ratio for coat color will be 100% Nn (heterozygous), resulting in a phenotypic ratio of 100% normal coat color as N is dominant. For eye color, the Punnett square is as follows:

b b
B Bb Bb
The genotypic ratio for eye color is 100% Bb (heterozygous) and the phenotypic ratio is 100% brown eyes as brown (B) is dominant over blue (b). Thus, all offspring will have normal coat color and brown eyes.

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