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Answer :
With Georgia's motorcycle at over 4.5 m long and having a mass of 235 kg, Reid’s tangential speed is mathematically given as
vt=12.4m/s
What is Reid’s tangential speed?
Generally, the equation for the Conservation of momentum is mathematically given as
mn=m1+m2
Therefore
mn=235+72
mn=307
Therefore
Fc=mn*a
THerefore
[tex]vt=\sqrt{\frac{rFc}{mn}}\\\\vt=\sqrt{\frac{25*1850}{307}}[/tex]
vt=12.4m/s
In conclusion, The tangential speed is
vt=12.4m/s
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Final answer:
To find Gregg Reid's tangential speed, the centripetal force formula is used, showing that Reid's tangential speed is approximately 12.27 m/s.
Explanation:
The question asks for the tangential speed of Gregg Reid's motorcycle and himself, moving in a circular path based on the centripetal force provided. Using the formula for centripetal force F = mv²/r, where F is the centripetal force, m is the mass, v is the tangential speed, and r is the radius of the circular path, we can solve for the tangential speed v. Given F = 1850 N, total m (mass of Reid + motorcycle) = 235 kg + 72 kg = 307 kg, and r = 25.0 m:
v = √(Fr/m) = √(1850 * 25.0 / 307) = √(150.489) ≈ 12.27 m/s
Therefore, Gregg Reid's tangential speed is approximately 12.27 m/s.
