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Answer :
Two jets leave an air base at the same time and travel in opposite directions. One jet travels 60(mi)/(h) faster than the other. If the two jets are 13,680miles apart after 9 hours, the rate of the slower jet is approximately 730 (mi/h), and the rate of the faster jet is 730 + 60 = 790 (mi/h).
Let's assume the rate of the slower jet is x (mi/h). Since the faster jet travels 60(mi/h) faster, its rate would be x + 60 (mi/h).
In 9 hours, the slower jet would have traveled a distance of 9x miles, and the faster jet would have traveled a distance of 9(x + 60) miles.
Since they are traveling in opposite directions, the sum of their distances should be equal to the total distance of 13,680 miles:
9x + 9(x + 60) = 13,680
Simplifying the equation:
9x + 9x + 540 = 13,680
18x = 13,680 - 540
18x = 13,140
x = 13,140 / 18
x ≈ 730
Therefore, the rate of the slower jet is approximately 730 (mi/h), and the rate of the faster jet is 730 + 60 = 790 (mi/h).
The rate of the slower jet is approximately 730 mi/h, and the rate of the faster jet is approximately 790 mi/h.
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