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Answer :
Final answer:
The molality of a 1.58 M aqueous solution of HClO4, given a solution density of 1.55 g/mL, is approximately 1.13 m.
Explanation:
To find the molality of an aqueous solution, you need to know the amount of solute (in moles) and the weight of the solvent (in kilograms). Given the molarity (M) of the solution, we know that there are 1.58 moles of HClO4 per liter of the solution. Additionally, we have the density of the solution (1.55 g/mL), which we can use to find the weight of the water in the solution.
To do this, note that 1 L of solution has a mass of 1.55 g/mL * 1000 mL = 1550 g. Given that the solution is aqueous, we assume the majority of this mass is due to water. The mass of 1.58 moles of HClO4 is around 150.5 g, so the mass of the water is approximately 1550 g – 150.5 g = 1399.5 g, or 1.3995 kg.
Thus, the molality of the solution is 1.58 moles / 1.3995 kg = 1.13 m.
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