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Answer :
We begin with the equation
$$
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - (x-4).
$$
**Step 1. Distribute and simplify each side.**
For the left side:
$$
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - 7 + 11 = \frac{1}{2}x + 4.
$$
For the right side, distribute the negative sign:
$$
\frac{1}{2}x - (x-4) = \frac{1}{2}x - x + 4 = -\frac{1}{2}x + 4.
$$
So, the equation becomes:
$$
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4.
$$
**Step 2. Eliminate the constant term by subtracting $4$ from both sides.**
Subtracting $4$ from both sides gives:
$$
\frac{1}{2}x + 4 - 4 = -\frac{1}{2}x + 4 - 4 \quad \Longrightarrow \quad \frac{1}{2}x = -\frac{1}{2}x.
$$
**Step 3. Solve for $x$.**
To isolate $x$, add $\frac{1}{2}x$ to both sides:
$$
\frac{1}{2}x + \frac{1}{2}x = -\frac{1}{2}x + \frac{1}{2}x.
$$
Simplify the left side:
$$
\left(\frac{1}{2} + \frac{1}{2}\right)x = 0 \quad \Longrightarrow \quad x = 0.
$$
Thus, the value of $x$ is $\boxed{0}$.
$$
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - (x-4).
$$
**Step 1. Distribute and simplify each side.**
For the left side:
$$
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - 7 + 11 = \frac{1}{2}x + 4.
$$
For the right side, distribute the negative sign:
$$
\frac{1}{2}x - (x-4) = \frac{1}{2}x - x + 4 = -\frac{1}{2}x + 4.
$$
So, the equation becomes:
$$
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4.
$$
**Step 2. Eliminate the constant term by subtracting $4$ from both sides.**
Subtracting $4$ from both sides gives:
$$
\frac{1}{2}x + 4 - 4 = -\frac{1}{2}x + 4 - 4 \quad \Longrightarrow \quad \frac{1}{2}x = -\frac{1}{2}x.
$$
**Step 3. Solve for $x$.**
To isolate $x$, add $\frac{1}{2}x$ to both sides:
$$
\frac{1}{2}x + \frac{1}{2}x = -\frac{1}{2}x + \frac{1}{2}x.
$$
Simplify the left side:
$$
\left(\frac{1}{2} + \frac{1}{2}\right)x = 0 \quad \Longrightarrow \quad x = 0.
$$
Thus, the value of $x$ is $\boxed{0}$.
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