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Answer :
To solve the division problem [tex]\(3 \div 208\)[/tex] using long division, we will determine the quotient and the remainder by following these steps:
1. Set up the long division: Write 208 under the long division symbol and 3 outside to the left.
2. Divide the first digit: Start with the first digit of 208, which is 2. Since 3 is larger than 2, it goes into 2 zero times. So, we move to the next digit.
3. Consider the first two digits: Now consider 20 (the first two digits of 208). How many times does 3 go into 20 without exceeding it?
- Multiply 3 by 6, which gives 18. This is the largest multiple less than 20.
- Write 6 above the division symbol as part of the quotient.
- Subtract 18 from 20, leaving 2 as the remainder.
4. Bring down the next digit: Bring down the next digit (8 from 208), making it 28.
5. Divide the new number: Now determine how many times 3 fits into 28:
- Multiply 3 by 9, which gives 27. This is the largest multiple of 3 less than 28.
- Write 9 next to the 6 in the quotient above the long division symbol.
- Subtract 27 from 28, leaving 1 as the remainder.
6. Finish up: There are no more digits to bring down, so the division is complete. The result is a quotient of 69 with a remainder of 1.
Therefore, [tex]\(3 \div 208\)[/tex] gives a quotient of 69 and a remainder of 1.
1. Set up the long division: Write 208 under the long division symbol and 3 outside to the left.
2. Divide the first digit: Start with the first digit of 208, which is 2. Since 3 is larger than 2, it goes into 2 zero times. So, we move to the next digit.
3. Consider the first two digits: Now consider 20 (the first two digits of 208). How many times does 3 go into 20 without exceeding it?
- Multiply 3 by 6, which gives 18. This is the largest multiple less than 20.
- Write 6 above the division symbol as part of the quotient.
- Subtract 18 from 20, leaving 2 as the remainder.
4. Bring down the next digit: Bring down the next digit (8 from 208), making it 28.
5. Divide the new number: Now determine how many times 3 fits into 28:
- Multiply 3 by 9, which gives 27. This is the largest multiple of 3 less than 28.
- Write 9 next to the 6 in the quotient above the long division symbol.
- Subtract 27 from 28, leaving 1 as the remainder.
6. Finish up: There are no more digits to bring down, so the division is complete. The result is a quotient of 69 with a remainder of 1.
Therefore, [tex]\(3 \div 208\)[/tex] gives a quotient of 69 and a remainder of 1.
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