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Analyze the following code:

A. The program displays n is 1000000000000.

B. The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an overflow, and the program is aborted.

C. The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an overflow, and the program continues to execute because Java does not report errors on overflow.

D. The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an underflow, and the program is aborted.

E. The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an underflow, and the program continues to execute because Java does not report errors on underflow.

Answer :

Final answer:

The correct answer is: The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an overflow and the program is aborted.

Explanation:

In Java, the int data type has a limited range, and if the result of a calculation exceeds that range, it causes an overflow. In this case, the result of 10000 * 10000 * 10000 is larger than the maximum value that can be stored in an int, resulting in an overflow.

An overflow occurs when a variable exceeds its maximum value and wraps around to a negative value or some other unexpected behavior. In Java, an overflow does not cause an underflow. Instead, it results in an undefined behavior, and in this case, the program is aborted.

Learn more about Overflow in Java here:

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