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Answer :
We start with the expression
[tex]$$
\sqrt[3]{5x} \cdot \sqrt[3]{25x^2}.
$$[/tex]
Using the property of cube roots that
[tex]$$
\sqrt[3]{a} \cdot \sqrt[3]{b} = \sqrt[3]{ab},
$$[/tex]
we combine the two cube roots into one:
[tex]$$
\sqrt[3]{5x} \cdot \sqrt[3]{25x^2} = \sqrt[3]{(5x)(25x^2)}.
$$[/tex]
Next, we multiply the radicands:
[tex]$$
(5x)(25x^2) = 125x^3.
$$[/tex]
Thus, the expression becomes
[tex]$$
\sqrt[3]{125x^3}.
$$[/tex]
Now, we notice that [tex]$125$[/tex] is a perfect cube since [tex]$125 = 5^3$[/tex], and [tex]$x^3$[/tex] is a perfect cube as well. Therefore, we can separate the cube root:
[tex]$$
\sqrt[3]{125x^3} = \sqrt[3]{125} \cdot \sqrt[3]{x^3} = 5 \cdot x.
$$[/tex]
So, the completely simplified form is
[tex]$$
5x.
$$[/tex]
[tex]$$
\sqrt[3]{5x} \cdot \sqrt[3]{25x^2}.
$$[/tex]
Using the property of cube roots that
[tex]$$
\sqrt[3]{a} \cdot \sqrt[3]{b} = \sqrt[3]{ab},
$$[/tex]
we combine the two cube roots into one:
[tex]$$
\sqrt[3]{5x} \cdot \sqrt[3]{25x^2} = \sqrt[3]{(5x)(25x^2)}.
$$[/tex]
Next, we multiply the radicands:
[tex]$$
(5x)(25x^2) = 125x^3.
$$[/tex]
Thus, the expression becomes
[tex]$$
\sqrt[3]{125x^3}.
$$[/tex]
Now, we notice that [tex]$125$[/tex] is a perfect cube since [tex]$125 = 5^3$[/tex], and [tex]$x^3$[/tex] is a perfect cube as well. Therefore, we can separate the cube root:
[tex]$$
\sqrt[3]{125x^3} = \sqrt[3]{125} \cdot \sqrt[3]{x^3} = 5 \cdot x.
$$[/tex]
So, the completely simplified form is
[tex]$$
5x.
$$[/tex]
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