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Answer :
There are 0.596 moles of nickel(III) phosphate in 98.3 grams of the compound.
To calculate the number of moles in 98.3 grams of nickel(III) phosphate, we need to use the formula:
moles = mass (in grams) / molar mass
First, we need to find the molar mass of nickel(III) phosphate. To do this, we need to know the chemical formula of the compound. Nickel(III) phosphate has the chemical formula NiPO4. The molar mass of nickel(III) phosphate can be calculated by adding the atomic masses of nickel, phosphorus, and four oxygen atoms:
Molar mass of NiPO4 = (1 x atomic mass of Ni) + (1 x atomic mass of P) + (4 x atomic mass of O)
Molar mass of NiPO4 = (1 x 58.69) + (1 x 30.97) + (4 x 15.99)
Molar mass of NiPO4 = 164.67 g/mol
Now we can use the formula above to calculate the number of moles:
moles = 98.3 g / 164.67 g/mol
moles = 0.596 moles
Therefore, there are 0.596 moles of nickel(III) phosphate in 98.3 grams of the compound.
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