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Answer :
The maximum height of the projectile is 226 feet
How to calculate the maximum height of an object?
Given the equation of the height modelled as h(t) = –16t^2 + 48t + 190
The ball reaches the maximum height at the point where v = dh/dt = 0
dh/dt = -32t + 48
32t = 48
t = 1.5s
Get the maximum height;
h(1.5) = –16(1.5)^2 + 48(1.5) + 190
h(1.5) = -36 + 72 + 190
h(1.5) = 226 feet
Hence the maximum height of the projectile is 226 feet
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