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Limestone (CaCO₃) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how many grams of quicklime can be produced from 1 kg of limestone.

Answer :

Final answer:

From 1 kg of limestone, 560 grams of quicklime can be produced. This calculation follows the law of conservation of mass and assumes a 100% yield of CaO.

Explanation:

To calculate how many grams of quicklime (CaO) can be produced from 1 kg of limestone (CaCO₃), we reference a chemical reaction where 10.0 grams of CaCO₃ produce 5.6 grams of CaO. This provides a direct ratio that can be scaled up to 1 kg (1000 grams) of CaCO₃.

First, we set up a proportion based on the ratio from the example: (5.6 g CaO / 10 g CaCO₃) = (x g CaO / 1000 g CaCO₃). When we solve for x, we multiply both sides by 1000 g CaCO₃ to isolate x on one side of the equation, yielding x = (5.6 g CaO / 10 g CaCO₃) × 1000 g CaCO₃.

Calculating this, x = 560 g of CaO. Thus, 560 grams of quicklime can be produced from 1 kg of limestone, confirming the relationship between the reactants and products adheres to the law of conservation of mass and allowing 100% yield of CaO by letting the CO₂ escape.

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