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The population, [tex]p[/tex], of a town after [tex]t[/tex] years is represented using the equation [tex]p=10000(1.04)^{-t}[/tex]. Which of the following is an equivalent expression?

A. [tex]p=10000\left(\frac{1}{25}\right)^t[/tex]

B. [tex]p=10000\left(\frac{25}{26}\right)^t[/tex]

C. [tex]p=10000\left(\frac{26}{25}\right)^t[/tex]

Answer :

To solve this problem step-by-step, let's look at the given equation and the options we're comparing it to.

The given equation is:
[tex]\[ p = 10000 (1.04)^{-t} \][/tex]

We want to find which of the following expressions is equivalent to this equation:
1. [tex]\( p = 10000 \left(\frac{1}{25}\right)^t \)[/tex]
2. [tex]\( p = 10000 \left(\frac{25}{26}\right)^t \)[/tex]
3. [tex]\( p = 10000 \left(\frac{26}{25}\right)^t \)[/tex]

Let's analyze the given equation and use properties of exponents to find the equivalent expression.

### Step-by-Step Solution:

1. Understanding the given equation:
[tex]\[ p = 10000 (1.04)^{-t} \][/tex]

2. Rewrite the base [tex]\( 1.04 \)[/tex] in a different form:
Recall that [tex]\( 1.04 = \frac{104}{100} = \frac{26}{25} \)[/tex].

3. Substitute [tex]\( \frac{26}{25} \)[/tex] into the given equation:
[tex]\[ p = 10000 \left( \frac{26}{25} \right)^{-t} \][/tex]

4. Apply the property of exponents:
Using the property of exponents [tex]\( a^{-b} = \left( \frac{1}{a} \right)^b \)[/tex], we can rewrite [tex]\( \left( \frac{26}{25} \right)^{-t} \)[/tex] as:
[tex]\[ \left( \frac{26}{25} \right)^{-t} = \left( \frac{25}{26} \right)^t \][/tex]

5. Substitute this result back into the equation:
[tex]\[ p = 10000 \left( \frac{25}{26} \right)^t \][/tex]

So the expression equivalent to the given equation [tex]\( p = 10000 (1.04)^{-t} \)[/tex] is:
[tex]\[ p = 10000 \left( \frac{25}{26} \right)^t \][/tex]

### Conclusion

The correct equivalent expression is:
[tex]\[ p = 10000 \left(\frac{25}{26}\right)^t \][/tex]

Thus, the answer is:
[tex]\[ \boxed{10000 \left( \frac{25}{26} \right)^t} \][/tex]

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