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Answer :
Final answer:
Using the range of a projectile formula in Physics, and the given values in the question, the calculated landing spot of the projectile is approximately 128.9 m from the base of the building.
Explanation:
This question requires the use of projectile motion equations in Physics. The distance from the base of the building where the projectile lands, known as the range, can be calculated using the equation for the range of a projectile. This formula is R = v^2 sin(2θ) / g - 2vh sin(θ) / g, where v is the initial speed, θ is the angle, h is the initial height, and g is the gravity constant (~9.8 m/s^2).
Substituting the given values into the formula we get, R = (31.8 m/s)^2 sin (2 *47.7 ) / 9.8 m/s^2 - 2*31.8m/s*36.3* sin(47.7) / 9.8 m/s^2. When calculated, the result is about 128.9 m which matches one of your options, implying that the projectile lands 128.9 m from the base of the building.
Learn more about Projectile Motion here:
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