An aircraft has a net excess thrust of 14,000 lbs and weighs 36,000 lbs. If it starts from 30 kts, what is its velocity (in knots) after 15 seconds? "(which the answer is 141.218) you need this for the net part" How many feet down the runway would the aircraft in problem 4 be at rotation if Vr = 160 kts? (The aircraft is at 135 feet down the runway when it starts its takeoff and starts from 30 kts)

Question

09-06-2025
Physics

High School

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An aircraft has a net excess thrust of 14,000 lbs and weighs 36,000 lbs. If it starts from 30 kts, what is its velocity (in knots) after 15 seconds? "(which the answer is 141.218) you need this for the net part" How many feet down the runway would the aircraft in problem 4 be at rotation if Vr = 160 kts? (The aircraft is at 135 feet down the runway when it starts its takeoff and starts from 30 kts)

Answer :

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Final answer:

By applying Newton's second law and kinematics equations, we find acceleration using the given net thrust and weight. This gives us the final velocity after 15 seconds and the position of the aircraft on the runway when it reaches rotation speed.

Explanation:

To answer this question, we first need to realize that thrust is a force. Therefore, we can find the acceleration of the aircraft using Newton's second law, which states force equals mass times acceleration (F=ma). The mass of the aircraft is its weight divided by acceleration due to gravity, so we can set up the equation as 14,000 lbs = (36,000 lbs / 32.2 ft/s^2) * a. Solving this equation gives us the acceleration.

With acceleration determined, we can then use the equation v = u + at to calculate the final velocity after 15 seconds, where u is the initial velocity, a is the acceleration, and t is time. The initial velocity is given in knots and needs to be converted to feet per second.

Lastly, to find out how far the plane would be down the runway at rotation (Vr=160kts), we would use the equation s = ut + 0.5at^2, where s is the distance, u is the initial velocity, a is the acceleration and t is the time it takes to reach rotation speed.

Learn more about Kinematics here:

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