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The radioisotope strontium-90 has a half-life of 38.1 years. If a sample contains 36 mg of Sr-90, how many milligrams will remain after 152.4 years?

Answer :

Final answer:

The sample of Sr-90 will have a remaining amount of 2.25 mg after 152.4 years.

Explanation:

Strontium-90 is a radioisotope with a half-life of 38.1 years. This means that every 38.1 years, half of the initial amount of Sr-90 will decay. To calculate the amount of Sr-90 remaining after 152.4 years, we need to determine the number of half-lives that have passed. Since each half-life is 38.1 years, 152.4 years represents 4 half-lives.

To find the remaining amount, we can use the formula:

Amount remaining = Initial amount * (1/2)^(number of half-lives)

Substituting the given values:

Amount remaining = 36 mg * (1/2)^4 = 36 mg * (1/16) = 2.25 mg

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