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Answer :
The electric field strength 10.0 cm from the wire is 1032.25 N/C. It is given that the electric field strength at a distance of 5.0 cm from a long charged wire is 3700 N/C.
Since the charged wire is very long, its electric field is radial, and the magnitude of the electric field varies with distance r from the wire according to the equation:
E = λ/(2πεor), where λ is the linear charge density (charge per unit length), εo is the permittivity of free space (8.85 × 10−12 C2/Nm2), and 2πr is the circumference of a circle of radius r centered on the wire.
To find the electric field strength at a distance of 10.0 cm, substitute r = 10.0 cm = 0.1 m into the formula and solve for E:
E = λ/(2πεor)
E = (3700 N/C)(2π)(8.85 × 10−12 C2/Nm2)/(2 × 0.1 m)
E = 1032.25 N/C
Therefore, the electric field strength 10.0 cm from the wire is 1032.25 N/C.
The electric field strength 5.0 cm from a very long charged wire is 3700 N/C.
The electric field strength varies with distance r from the wire according to the equation: E = λ/(2πεor).
To find the electric field strength at a distance of 10.0 cm, substitute r = 10.0 cm = 0.1 m into the formula and solve for E:
E = λ/(2πεor)
E = (3700 N/C)(2π)(8.85 × 10−12 C2/Nm2)/(2 × 0.1 m)
E = 1032.25 N/C
Therefore, the electric field strength 10.0 cm from the wire is 1032.25 N/C.
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