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Answer :
Final answer:
Using the equations of motion, when a rocket is launched vertically upward with a speed of 21 m/s, it reaches a height of approximately 22.5 meters before its velocity becomes zero.
Explanation:
The height to which a toy rocket will rise can be calculated using the equations of motion, specifically the one that states that the final velocity squared equals the initial velocity squared plus two times the acceleration times the distance.
When the rocket reaches its maximum height, its velocity will be zero. Also, because gravity is acting downwards, the acceleration is negative (-9.8m/s^2).
So we get 0 = (21 m/s)^2 + 2*(-9.8 m/s^2) * d, where d is the distance. Solving for d, we get d = (21 m/s)^2 / (2*9.8 m/s^2) = 22.5 m. So the rocket goes up 22.5 meters.
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