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A mixture of gases at a total pressure of 145.0 kPa contains \(N_2\), \(CO_2\), and \(O_2\). The partial pressure of the \(N_2\) is 28.5 kPa, and the partial pressure of the \(CO_2\) is 76.0 kPa. What is the partial pressure of the \(O_2\)?

A) 40.5 kPa
B) 41.0 kPa
C) 40.0 kPa
D) 38.5 kPa

Answer :

Final answer:

The partial pressure in a gas mixture can be calculated by subtracting the partial pressures of the other gases from the total pressure. For this specific question, the partial pressure of O2 is 40.5 kPa.

Explanation:

Partial pressure in a gas mixture is the pressure exerted by each gas if it occupied the entire volume by itself. In this case, to find the partial pressure of O2, we subtract the partial pressures of N2 and CO2 from the total pressure of the mixture:

  • Partial pressure of O2 = Total pressure - Partial pressure of N2 - Partial pressure of CO2

Plugging in the values, we get Partial pressure of O2 = 145.0 kPa - 28.5 kPa - 76.0 kPa = 40.5 kPa.

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