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Answer :
Answer : The percentage of salt in the mixture is 73.65 %
Explanation : Given,
Mass of salt = 1.64 lb
Mass of water = 4.66 lb
First we have to calculate the mass of mixture.
Mass of mixture = Mass of salt + Mass of water
Mass of mixture = 1.64 + 4.66 = 6.3 lb
Now we have to calculate the percentage of salt in the mixture.
Formula used :
[tex]\% \text{ of salt}=\frac{\text{Mass of salt}}{\text{Mass of mixture}}\times 100[/tex]
Now put all the given vales in this formula, we get:
[tex]\% \text{ of salt}=\frac{4.64lb}{6.3lb}\times 100=73.65\%[/tex]
Therefore, the percentage of salt in the mixture is 73.65 %
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The percentage of the salt in the mixture is 26%
We shall begin the calculation to the question given above by obtaining the mass of the mixture. This can be obtained as follow:
Mass of salt = 1.64 lb
Mass of water = 4.66 lb
Mass of mixture =?
Mass of mixture = mass of salt + mass of water
Mass of mixture = 1.64 + 4.66
Mass of mixture = 6.3 lb
Finally, we shall determine the percentage of the salt in the mixture. This can be obtained as illustrated below:
Mass of salt = 1.64 lb
Mass of mixture = 6.3 lb
Percentage of the salt =?
Percentage of salt = [tex]\frac{mass of salt }{mass of mixture} * 100[/tex]
Percentage of salt = [tex]\frac{1.64}{6.3} * 100[/tex]
Percentage of salt = 26%
Therefore, the percentage of the salt in the mixture is 26%
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