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A shell explodes into two fragments, one fragment being 25 times heavier than the other. If any gas from the explosion has negligible mass, what is the relationship between the velocities of the two fragments?

Answer :

When a shell explodes into two fragments, with one fragment being 25 times heavier than the other and assuming negligible gas mass, the lighter fragment will experience a greater velocity than the heavier fragment due to the principle of conservation of momentum.

According to the principle of conservation of momentum, the total momentum of an isolated system remains constant if no external forces act on it. In the case of the exploding shell, the initial momentum of the system is zero since the shell is at rest before the explosion. After the explosion, the total momentum of the system will still be zero.

Since one fragment is 25 times heavier than the other, the lighter fragment must have a greater velocity to compensate for the difference in mass and ensure the conservation of momentum. This is because momentum is a product of mass and velocity. If the heavier fragment has a lower velocity, the lighter fragment must have a higher velocity to maintain the balance.

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