Answer :

Final answer:

To find the number of atoms in 156 g of Al2Li, calculate the number of moles based on the molar mass and multiply by Avogadro's number and the number of atoms per formula unit, resulting in approximately 5.52 x 10^24 atoms.

Explanation:

To calculate the number of atoms in 156 g of Al2Li, we need to first determine the molar mass of Al2Li and then use this information to calculate the number of moles of Al2Li in the sample. Using the molar masses of aluminium (Al) and lithium (Li), we find that the molar mass of Al2Li is approximately 50.96 g/mol (2 x 26.98 g/mol for Al + 6.94 g/mol for Li).

Next, we divide the mass of the Al2Li sample by its molar mass to find the number of moles:

Number of moles of Al2Li = 156 g / 50.96 g/mol = 3.06 moles

Since the formula Al2Li indicates there are two aluminium atoms and one lithium atom per formula unit, we have a total of 3 atoms per formula unit. To find the total number of atoms, we multiply the number of moles of Al2Li by Avogadro's number (6.022 x 10^23 atoms/mol), and then by 3:

Total number of atoms in 156 g of Al2Li = 3.06 moles x 6.022 x 10^23 atoms/mol x 3 atoms/mol = 5.52 x 10^24 atoms.

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