High School

We appreciate your visit to The coofficient of kinetie friction between a sulicase and the floor is 0 272 You may want to review Pages 196 203 If the suitcase. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

The coofficient of kinetie friction between a sulicase and the floor is 0.272. You may want to review (Pages 196 - 203) If the suitcase has a mass of 80.0 kg, how far can it be pushed across the level floor with 600 J of work?

Answer :

The suitcase can be pushed approximately 2.815 meters across the level floor with 600 J of work.

To solve this problem, we need to use the work-energy principle. According to this principle, the work done on an object is equal to the change in its kinetic energy.

The work done on the suitcase can be calculated using the equation:

Work = Force × Distance

In this case, the force is the force of friction between the suitcase and the floor. The work done is given as 600 J.

Since the force of friction is opposing the motion, it is equal to the product of the coefficient of kinetic friction and the normal force. The normal force is equal to the weight of the suitcase, which can be calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s²).

Force of friction = coefficient of kinetic friction × normal force

Now, we can calculate the normal force:

Normal force = mass × acceleration due to gravity

Normal force = 80.0 kg × 9.8 m/s² = 784 N

Substituting the values into the equation for the force of friction:

Force of friction = 0.272 × 784 N = 213.248 N

Now, we can rearrange the equation for work to solve for distance:

Work = Force × Distance

Distance = Work / Force

Distance = 600 J / 213.248 N ≈ 2.815 m

Learn more about coefficient of kinetic friction from the given link:

https://brainly.com/question/28522249

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