We appreciate your visit to In the laboratory a student finds that it takes 94 8 Joules to increase the temperature of 10 7 grams of solid titanium from 20. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
To find the specific heat of the titanium, you use the formula for specific heat capacity: c = q / (m * ∆T). Given the conditions in the problem, the specific heat capacity of titanium is calculated to be 0.487 J/g°C.
Explanation:
The specific heat capacity of a substance can be calculated using the formula:
c = q / (m * ∆T),
where 'c' is the specific heat capacity, 'q' is the heat energy absorbed or released, 'm' is the mass of the substance, and '∆T' is the change in temperature.
Given:
q = 94.8 J, m = 10.7 g, ∆T = (38.8-20.6)°C = 18.2°C.
Substituting these values into the formula gives:
c = 94.8 J / (10.7 g * 18.2°C) = 0.487 J/g°C.
So, the specific heat capacity of titanium is 0.487 J/g°C.
Learn more about specific heat capacity here:
https://brainly.com/question/29766819
#SPJ11
Thanks for taking the time to read In the laboratory a student finds that it takes 94 8 Joules to increase the temperature of 10 7 grams of solid titanium from 20. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
