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Answer :
To determine how many molecules are in 37.6 liters of methane (CH₄), we can follow these steps:
1. Understand the Context:
Methane is a gas, and we are considering its volume at Standard Temperature and Pressure (STP). Under these conditions, we use the concept of molar volume.
2. Use Molar Volume:
At STP, 1 mole of any gas occupies 22.4 liters. This value is the molar volume of a gas at STP.
3. Calculate Moles of Methane:
To find out how many moles of methane are in 37.6 liters, you divide the given volume (37.6 liters) by the molar volume (22.4 liters/mole):
[tex]\[
\text{Moles of methane} = \frac{37.6 \text{ L}}{22.4 \text{ L/mole}} \approx 1.68 \text{ moles}
\][/tex]
4. Use Avogadro's Number:
Avogadro's number tells us that 1 mole of any substance contains approximately [tex]\(6.022 \times 10^{23}\)[/tex] molecules.
5. Calculate the Number of Molecules:
Multiply the number of moles by Avogadro's number to find the total number of molecules:
[tex]\[
\text{Molecules of methane} = 1.68 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} \approx 1.01 \times 10^{24} \text{ molecules}
\][/tex]
As a result, 37.6 liters of methane contain approximately [tex]\(1.01 \times 10^{24}\)[/tex] molecules.
1. Understand the Context:
Methane is a gas, and we are considering its volume at Standard Temperature and Pressure (STP). Under these conditions, we use the concept of molar volume.
2. Use Molar Volume:
At STP, 1 mole of any gas occupies 22.4 liters. This value is the molar volume of a gas at STP.
3. Calculate Moles of Methane:
To find out how many moles of methane are in 37.6 liters, you divide the given volume (37.6 liters) by the molar volume (22.4 liters/mole):
[tex]\[
\text{Moles of methane} = \frac{37.6 \text{ L}}{22.4 \text{ L/mole}} \approx 1.68 \text{ moles}
\][/tex]
4. Use Avogadro's Number:
Avogadro's number tells us that 1 mole of any substance contains approximately [tex]\(6.022 \times 10^{23}\)[/tex] molecules.
5. Calculate the Number of Molecules:
Multiply the number of moles by Avogadro's number to find the total number of molecules:
[tex]\[
\text{Molecules of methane} = 1.68 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} \approx 1.01 \times 10^{24} \text{ molecules}
\][/tex]
As a result, 37.6 liters of methane contain approximately [tex]\(1.01 \times 10^{24}\)[/tex] molecules.
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