High School

We appreciate your visit to Calculate the electronegativity of fluorine from the following data Bond energy of H H bond E H H 104 2 text kcal mol 1 Bond. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Calculate the electronegativity of fluorine from the following data:

- Bond energy of H-H bond: \( E_{H-H} = 104.2 \, \text{kcal mol}^{-1} \)
- Bond energy of F-F bond: \( E_{F-F} = 36.6 \, \text{kcal mol}^{-1} \)
- Bond energy of H-F bond: \( E_{H-F} = 134.6 \, \text{kcal mol}^{-1} \)
- Electronegativity of Hydrogen (\( X_H \)) = 2.1

Choose the correct electronegativity of fluorine:

A. 3.87
B. 2.76
C. -3.87
D. -2.76

Answer :

The electronegativity of fluorine is 3.87. Option A is the correct answer.

To calculate the electronegativity of fluorine, we can use the concept of bond energies and the Pauling scale.

Given:

- Bond energy of H-H bond (Eₕ₋ₕ) = 104.2 kcal/mol

- Bond energy of F-F bond (E₋) = 36.6 kcal/mol

- Bond energy of H-F bond (Eₕ₋) = 134.6 kcal/mol

- Electronegativity of hydrogen (Xₕ) = 2.1

1. Calculate the electronegativity of fluorine (X₋) using the bond energies:

X₋ - Xₕ = √(Eₕ₋ - Eₕ₋ₕ) - √(E₋ - Eₕ₋ₕ)

X₋ - 2.1 = √(134.6 - 104.2) - √(36.6 - 104.2)

X₋ - 2.1 = √30.4 - √(-67.6)

X₋ - 2.1 = 5.51 - 8.22

X₋ - 2.1 = -2.71

X₋ = -2.71 + 2.1

X₋ = 3.87

Therefore, the electronegativity of fluorine is 3.87.

The correct answer is option A.

Thanks for taking the time to read Calculate the electronegativity of fluorine from the following data Bond energy of H H bond E H H 104 2 text kcal mol 1 Bond. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada