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Answer :
Sure, let's solve the problem step by step.
1. Probability of Heterozygous Offspring (Ww) When Ww is Crossed with ww:
- We are given a heterozygous male with genotype [tex]\( Ww \)[/tex] and a homozygous recessive female with genotype [tex]\( ww \)[/tex].
- To find the possible offspring genotypes, we can use a Punnett square:
[tex]\[
\begin{array}{c|c|c}
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\end{array}
\][/tex]
- From the Punnett square, the possible offspring genotypes are: [tex]\( Ww, ww, Ww, \)[/tex] and [tex]\( ww \)[/tex].
- Out of these four possibilities, two are heterozygous [tex]\( Ww \)[/tex].
- Therefore, the probability of getting a heterozygous offspring is 2 out of 4, which is [tex]\( \frac{2}{4} = 0.5 \)[/tex] or 50%.
2. Probability of Homozygous Recessive Offspring (ww) When WW is Crossed with WW:
- If a heterozygous [tex]\( WW \)[/tex] individual is crossed with another [tex]\( WW \)[/tex], the offspring can only be homozygous dominant ([tex]\( WW \)[/tex]).
- The possible combinations using a Punnett square would be:
[tex]\[
\begin{array}{c|c|c}
& W & W \\
\hline
W & WW & WW \\
\hline
W & WW & WW \\
\end{array}
\][/tex]
- All the offspring will be homozygous dominant ([tex]\( WW \)[/tex]).
- Therefore, the probability of getting a homozygous recessive offspring [tex]\( ww \)[/tex] is 0.
In conclusion, the probability of getting a heterozygous offspring when [tex]\( Ww \)[/tex] is crossed with [tex]\( ww \)[/tex] is 0.5 (50%), and the probability of getting a homozygous recessive offspring [tex]\( ww \)[/tex] when [tex]\( WW \)[/tex] is crossed with [tex]\( WW \)[/tex] is 0.
1. Probability of Heterozygous Offspring (Ww) When Ww is Crossed with ww:
- We are given a heterozygous male with genotype [tex]\( Ww \)[/tex] and a homozygous recessive female with genotype [tex]\( ww \)[/tex].
- To find the possible offspring genotypes, we can use a Punnett square:
[tex]\[
\begin{array}{c|c|c}
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\end{array}
\][/tex]
- From the Punnett square, the possible offspring genotypes are: [tex]\( Ww, ww, Ww, \)[/tex] and [tex]\( ww \)[/tex].
- Out of these four possibilities, two are heterozygous [tex]\( Ww \)[/tex].
- Therefore, the probability of getting a heterozygous offspring is 2 out of 4, which is [tex]\( \frac{2}{4} = 0.5 \)[/tex] or 50%.
2. Probability of Homozygous Recessive Offspring (ww) When WW is Crossed with WW:
- If a heterozygous [tex]\( WW \)[/tex] individual is crossed with another [tex]\( WW \)[/tex], the offspring can only be homozygous dominant ([tex]\( WW \)[/tex]).
- The possible combinations using a Punnett square would be:
[tex]\[
\begin{array}{c|c|c}
& W & W \\
\hline
W & WW & WW \\
\hline
W & WW & WW \\
\end{array}
\][/tex]
- All the offspring will be homozygous dominant ([tex]\( WW \)[/tex]).
- Therefore, the probability of getting a homozygous recessive offspring [tex]\( ww \)[/tex] is 0.
In conclusion, the probability of getting a heterozygous offspring when [tex]\( Ww \)[/tex] is crossed with [tex]\( ww \)[/tex] is 0.5 (50%), and the probability of getting a homozygous recessive offspring [tex]\( ww \)[/tex] when [tex]\( WW \)[/tex] is crossed with [tex]\( WW \)[/tex] is 0.
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