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Answer :
Final answer:
To find the energy required to heat 1.90 kg of iron from 1.7°C to 19.6°C, convert the mass to grams, calculate the temperature change, and use the heat equation. The energy calculated is 15268.29 J, which does not match any of the given multiple-choice options.
Explanation:
To calculate the energy required to heat 1.90 kg of iron from 1.7°C to 19.6°C, we can use the formula q = mcΔT, where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
To begin with, convert mass from kilograms to grams:
1.90 kg = 1900 g, since 1 kg = 1000 g.
Next, calculate the change in temperature (ΔT):
19.6°C - 1.7°C = 17.9°C.
Now, compute the energy required using the given specific heat capacity (0.449 J/g°C):
q = (1900 g) × (0.449 J/g°C) × (17.9°C) = 15268.29 J.
None of the options a) 145 J, b) 325 J, c) 520 J, or d) 710 J is correct, since the calculated energy is 15268.29 J, which is significantly higher than any of the provided options.
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