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1.57 moles of hydrochloric acid is dissolved in 7.00 L of water. What is the pH of the solution? Answer the question with the correct number of significant figures.

Answer :

The pH of the solution is 0.65.

To find the pH of the solution, we need to first calculate the concentration of HCl in moles per liter (Molarity).

Molarity (M) = moles of solute/volume of solution (in liters)

In this case, we have 1.57 moles of HCl dissolved in 7.00 L of water:

Molarity (HCl) = 1.57 moles / 7.00 L = 0.224 M

The pH of a solution can be calculated using the equation:

pH = -log[H+]

Since HCl is a strong acid, it completely dissociates in water, and the concentration of H+ ions is equal to the concentration of HCl.

Therefore, the pH of the solution can be calculated as:

pH = -log(0.224) = 0.650

Rounding the answer to the correct number of significant figures, the pH of the solution is 0.65.

Learn more about pH at https://brainly.com/question/172153

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