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Answer :
Let's go through each part of the question step by step:
Output of: print("Welcome To My Blog"[2:6] + "Welcome To My Blog"[5:9])
- The first slice, [2:6], extracts from the string starting at index 2 up to, but not including, index 6. This results in "lcom".
- The second slice, [5:9], extracts from index 5 up to, but not including, index 9, which is "me T".
- Concatenating these two results in "lcomme T".
Output of: print (10>20)
- This statement checks if 10 is greater than 20, which is false. Therefore, it outputs False.
Steps to perform an Insert query in a database connectivity application for the 'student' table with values (1, 'AMIT', 22):
- Step 1: Establish a connection to the database using a connection string or credentials.
- Step 2: Create a cursor object using the established connection. This object will allow you to execute SQL queries.
- Step 3: Write the SQL Insert Query: INSERT INTO student (rollno, name, age) VALUES (1, 'AMIT', 22).
- Step 4: Execute the query using the cursor object.
- Step 5: Commit the transaction to make sure changes are saved to the database.
- Step 6: Close the cursor and database connection to free up resources.
Output of: print([x+y for x in 'ball' for y in 'boy'])
- This uses a list comprehension to create combinations of each character from 'ball' with each character from 'boy'. The resulting list is ['bb', 'bo', 'by', 'ab', 'ao', 'ay', 'lb', 'lo', 'ly', 'lb', 'lo', 'ly'].
Output of:
d = {1:100, 2:200}
for x,y in d:
print(x*y, end="#")- This code will raise an error because iterating over a dictionary directly returns keys. The correct way would be for x, y in d.items():, which would print 100#400#.
Output of:
l = [1,2,5,6,7,9,10,22,38]
k = [el*r for el in l if (el-4)>1 for r in l[:4]]
print(k)- For elements where (el-4)>1 is true, multiply with each element in l[:4]. The result is [10, 20, 50, 60, 12, 24, 60, 72, 84, 168, 210, 252, 30, 60, 150, 180].
Output of: print(L[2:5]) given L=[1,3,6,82,5,7,11,92]
- Slices from index 2 to 4, resulting in [6, 82, 5].
Output of:
marks = {"Ashok":98.6, "Ramesh":95.5}
print(list(()))- This will simply print an empty list [] as list(()) converts an empty tuple to a list.
Output of: print(75.0/4 + (2**3))
- Carry out the calculation: [tex]\frac{75.0}{4} = 18.75[/tex] and [tex](2^3) = 8[/tex]; thus, the result is [tex]18.75 + 8 = 26.75[/tex].
Output of:
L=[4,3,6,8,2]
Lst=[]
for i in range(len(L)):
if L[i]%2==0:
t=(L[i],L[i]**2)
Lst.append(t)
print(Lst)- Identifies even numbers and adds a tuple with their square: [(4, 16), (6, 36), (8, 64), (2, 4)].
Output of:
a = [0, 1, 2, 3]
del a[:]
print(a)- Deletes all items in the list, resulting in an empty list [].
Output of:
a=[1,2,3,4]
b=[sum(a[0:x+1]) for x in range(0,len(a))]
print (b)- Computes cumulative sums: [1, 3, 6, 10].
Output of:
data = [1,2,4,5]
for x in data:
x = x + 10
print(data)- The list remains unchanged as data = [1, 2, 4, 5] because changes to x don't affect the list.
Output of:
a=[1,2,3,4,5]
for i in range(1,5):
a[i-1]=a[i]
for i in range(0,5):
print(a[i],end=" ")- Shifts elements left, filling with the last value: 2 3 4 5 5 .
Output of:
l=[1,2,3,4,5]
l[1:2]=[7,8]
print(l)- Replaces the element at index 1 with list [7,8], yielding [1, 7, 8, 3, 4, 5].
Given: tp = (1,2,3,4,5,6), Which statements give the same output?
- print(tp[:-1]) and print(tp[0:5]) both give (1, 2, 3, 4, 5). So, options 1 and 2 are correct.
Output of: print(tup1[3:7:2]) given tup1=(10,20,30,40,50,60,70,80,90)
- Slicing from index 3 to 6 with a step of 2 results in (40, 60).
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