We appreciate your visit to Chapter 13 The rate constant for a reaction at 25 C is 0 010 s ¹ and its activation energy is 35 8 kJ mol. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The rate constant at 50°C is approximately 0.021 s⁻¹. The answer is a.
The Arrhenius equation relates the rate constant of a reaction to its activation energy and temperature:
[tex]k = Ae^{(-Ea/RT)[/tex]
where k is the rate constant, Ea is the activation energy, R is the gas constant (8.314 J/mol•K), T is the temperature in Kelvin, and A is the pre-exponential factor, which is a constant that depends on the specific reaction.
To find the rate constant at 50°C, we need to convert the temperature to Kelvin:
T = 50°C + 273.15 = 323.15 K
We can then use the Arrhenius equation and the given values to solve for the rate constant at 50°C:
[tex]k_2 = Ae^_(-Ea/RT_2)[/tex]
[tex]= (0.010 s^{-1})e^{(-35,800 J/mol / (8.314 J/mol•K * 323.15 K))[/tex]
= 0.021 s⁻¹
Therefore, the rate constant at 50°C is approximately 0.021 s⁻¹, which corresponds to option A.
To know more about rate constant, refer here:
https://brainly.com/question/20305922#
#SPJ11
Thanks for taking the time to read Chapter 13 The rate constant for a reaction at 25 C is 0 010 s ¹ and its activation energy is 35 8 kJ mol. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada