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Answer :
Final answer:
The rate constant for the given second-order reaction is approximately 0.0058.
Explanation:
The rate constant can be calculated using the formula for a second-order reaction:
k = (2 * [A]₀) / t₁/₂
First, we need to convert the half-life from minutes to seconds:
t₁/₂ = 39.1 * 60 = 2346 seconds
Then, we can substitute the values into the formula:
k = (2 * 6.84) / 2346
k ≈ 0.0058
Therefore, the rate constant is approximately 0.0058.
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