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Answer :
d. HBr + Sr(OH)₂ → SrBr₂ + H₂O is the correct equation representing the acid-base neutralization reaction between hydrobromic acid (HBr) and strontium hydroxide (Sr(OH)₂).
In a neutralization reaction, an acid reacts with a base to produce a salt and water. Hydrobromic acid (HBr) is a strong acid, and strontium hydroxide (Sr(OH)₂) is a strong base.
When these two substances react, the hydrogen ions (H⁺) from the acid combine with the hydroxide ions (OH⁻) from the base to form water (H₂O).
The remaining ions, bromide (Br⁻) from HBr and strontium (Sr²⁺) from Sr(OH)₂, combine to form the salt strontium bromide (SrBr₂). The balanced equation for this reaction, considering the stoichiometry, is:
2HBr + Sr(OH)₂ → SrBr₂ + 2H₂O
This equation shows that two moles of HBr react with one mole of Sr(OH)₂ to produce one mole of SrBr₂ and two moles of water, satisfying the requirement for both mass and charge balance. Thus, option d is correct.
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