We appreciate your visit to The A string on a violin has a fundamental frequency of 440 Hz The length of the vibrating portion is 30 8 cm and it. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Tension must the string be placed is 86.75 N.
What is Tension?
In physics, tension is defined as the pulling force that is transmitted axially by a string, rope, chain, or similar object, or by each end of a rod, truss member, or other comparable three-dimensional object. Tension can also be defined as the action-reaction pair of forces acting at each end of the aforementioned elements.
f = 440 Hz
l = 32 cm = 0.32 m
m = 0.35 g = 0.35 x 10^-3 kg
μ = m / l = 0.35 x 10^-3 / 0.32 = 1.094 x 10^-3 kg/m
The formula for the fundamental frequency is given by
[tex]f=\frac{1}{2 l} \sqrt{\frac{T}{\mu}}$$[/tex]
Where, T be the tension
[tex]$$\begin{aligned}& 440=\frac{1}{2 \times 0.32} \sqrt{\frac{T}{1.094 \times 10^{-3}}} \\& 281.6=\sqrt{\frac{T}{1.094 \times 10^{-3}}}\end{aligned}$$[/tex]
T = 86.75 N
Thus, the tension in the string is 86.75 N.
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